Users from /etc/passwd

~12 min

Parse the classic colon-delimited file and extract real users.

/etc/passwd has one account per line, colon-delimited; field 1 is the username, field 3 the numeric UID:

root:x:0:0:root:/root:/bin/bash
student:x:1000:1000::/home/student:/bin/bash
daemon:x:1:1::/usr/sbin:/usr/sbin/nologin

Human accounts have UID ≥ 1000. Read: first line = integer N, then N passwd lines. Print the username of every human account (UID ≥ 1000), one per line, in input order.

For the sample above (N=3) the output is:

student

Hint: parts = line.split(":"), username = parts[0], uid = int(parts[2]).

Language: python · Judge0

// sample tests

stdin "3\nroot:x:0:0:root:/root:/bin/bash\nstudent:x:1000:1000::/home/student:/bin/bash\ndaemon:x:1:1::/usr/sbin:/usr/sbin/nologin" → stdout "student"
stdin "2\nalice:x:1000:1000::/home/alice:/bin/bash\nbob:x:1001:1001::/home/bob:/bin/zsh" → stdout "alice\nbob"

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